Maths Olympiad Prep

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Geometry Difficulty 5.7 AIME, harder Prove it

B2. Let ABCA B C be an acute-angled triangle and DD a point inside this triangle such that BAD=DCB\angle B A D = \angle D C B and CBD=DAC\angle C B D = \angle D A C. Prove that the lines ADA D and BCB C are perpendicular.

Solution

B2. In triangle ABCABC, the angle BAC\angle BAC is 3030^{\circ}, and PP is a point inside this triangle. The reflections of point PP across the sides BCBC, CACA, and ABAB are denoted as PAP_{A}, PBP_{B}, and PCP_{C}, respectively. Suppose that PAPBPCP_{A} P_{B} P_{C} is an equilateral triangle. Prove that BPC=90\angle BPC = 90^{\circ}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.