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Geometry Difficulty 5.1 AIME, harder Find the answer

Example 5 As shown in Figure 1, it is known that point PP moves on the circle x2+(y4)2=1x^{2}+(y-4)^{2}=1, and point QQ moves on the ellipse x29+y2=1\frac{x^{2}}{9}+y^{2}=1. Try to find the maximum value of PQ|PQ|.
(1994, Sichuan Province High School Mathematics Competition)

A number or a short expression. Spacing and $ signs are ignored.

Solution

Analysis: First, fix point QQ on the ellipse. It is evident that PQ|P Q| is maximized when PQP Q passes through the center O1O_{1}. Therefore, to find the maximum value of PQ|P Q|, we only need to find the maximum value of O1Q\left|O_{1} Q\right|.
Let Q(x,y)Q(x, y), then
O1Q2=x2+(y4)2 \left|O_{1} Q\right|^{2}=x^{2}+(y-4)^{2} \text {. }

Since QQ is on the ellipse, we have x29+y2=1\frac{x^{2}}{9}+y^{2}=1, which means
x2=9(1y2) x^{2}=9\left(1-y^{2}\right) \text {. }

Substituting equation (2) into equation (1) yields,
O1Q2=9(1y2)+(y4)2=8y28y+25=8(y+12)2+27. \begin{array}{l} \left|O_{1} Q\right|^{2}=9\left(1-y^{2}\right)+(y-4)^{2} \\ =-8 y^{2}-8 y+25=-8\left(y+\frac{1}{2}\right)^{2}+27 . \end{array}

Since point QQ moves on the ellipse, 1y1-1 \leqslant y \leqslant 1. Therefore, when y=12y=-\frac{1}{2},
O1Qmax=33,PQmax=33+1 \left|O_{1} Q\right|_{\max }=3 \sqrt{3},|P Q|_{\max }=3 \sqrt{3}+1 \text {. }

Note: In problems involving the analytic geometry of circles, it is often necessary to flexibly apply the relevant properties of circles.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.