## Solution
The desired decomposition of vector x is:
x=α⋅p+β⋅q+γ⋅r
Or in the form of a system:
⎩⎨⎧α⋅p1+β⋅q1+γ⋅r1=x1α⋅p2+β⋅q2+γ⋅r2=x2α⋅p3+β⋅q3+γ⋅r3=x3
We obtain:
⎩⎨⎧3β−γ=−155α+2β+γ=5α−β=6
Add the third row multiplied by -5 to the second row:
⎩⎨⎧3β−γ=−157β+γ=−25α−β=6
Add the first row to the second row:
⎩⎨⎧3β−γ=−1510β=−40α−β=6
⎩⎨⎧3β−γ=−15β=−4α−β=6⎩⎨⎧3⋅(−4)−γ=−15β=−4α−(−4)=6⎩⎨⎧−γ=−3β=−4α=2⎩⎨⎧γ=3β=−4α=2
The desired decomposition:
x=2p−4q+3r
## Problem Kuznetsov Analytic Geometry 2−21