Maths Olympiad Prep

Library / /37 of 520

Algebra Difficulty 4.7 AIME Find the answer

6. Given that xx, yy, and zz are real numbers, and x2+y2+z2=1x^{2}+y^{2}+z^{2}=1. Then m=xy+yz+zx()m=x y+y z+z x(\quad).

Pick one

Solution

6.C

Translate the text above into English, please retain the original text's line breaks and format, and output the translation result directly.

However, it seems there was a misunderstanding in your request. The text "6.C" does not require translation as it is already in a form that is the same in both Chinese and English. If you have more text to translate or need further assistance, please let me know!

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.