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Number theory Difficulty 3.4 AMC 10/12 Find the answer

Three primes p,qp,q, and rr satisfy p+q=rp+q = r and 1<p<q1 < p < q. Then pp equals

Pick one

Solution

We are given that p,qp,q and rr are primes. In order for pp and qq to sum to another prime, either pp or qq has to be even, because the sum of two odd numbers would be even, and the only even prime is 22 (but p+q=2p + q = 2 would have, as the only solution in positive integers, p=q=1p = q = 1, and 11 is not prime). Thus, with one of either pp or qq being even, either pp or qq must be 22, and as p<qp < q, we deduce p=2p = 2 (as 22 is the smallest prime). This means the answer is (A) 2\boxed{\textbf{(A)}\ 2}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.