Maths Olympiad Prep

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Combinatorics Difficulty 7.0 National olympiad, round 2 Prove it

Given is a positive integer nn and a game board consisting of n+1n+1 square fields arranged side by side, numbered from 0 to nn from left to right. At the beginning of the game, nn game pieces are located on field No. 0, and the other fields are empty.
A patient player now chooses for each move a field with k0k \neq 0 pieces and moves one of them at most kk fields to the right. The piece must remain on the board. His goal is to move all nn pieces to field No. nn with a sequence of such moves.
Prove that the player cannot achieve this goal in fewer than n1+n2+n3++nn\left\lceil\frac{n}{1}\right\rceil+\left\lceil\frac{n}{2}\right\rceil+\left\lceil\frac{n}{3}\right\rceil+\ldots+\left\lceil\frac{n}{n}\right\rceil moves. (Here, x\lceil x\rceil denotes the smallest integer not less than xx.)

Solution

The game pieces are indistinguishable and all have the same starting and target field. Therefore, a patient player can invent a rule that tells him which of the pieces on the selected field he should move.
A possible rule is obtained by firmly numbering the pieces from 1 to nn and in each move, after selecting the field, moving the piece with the highest number there.
Assume he moves the piece with the number k(1kn)k(1 \leq k \leq n) to the right in this way. Then there cannot have been more than kk pieces on the selected field, because their numbers are at most equal to kk. Thus, piece kk is moved at most kk fields to the right each time. Since it is moved a total of exactly nn fields, at least nk\left\lceil\frac{n}{k}\right\rceil moves are required. This holds for all kk with 1kn1 \leq k \leq n. Summing over kk yields the minimum number of required game moves according to the problem statement. \square

Hint: A proof by complete induction is just as doomed to fail as considerations of seemingly "optimal" strategies whose optimality can only be locally convincingly justified.
It can be shown that the exact value of the given term can only be achieved for n=1,2,3,4,5,7n=1,2,3,4,5,7.

## Solutions to the 2nd Selection Test 2018/2019

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.