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Algebra Difficulty 2.9 Junior Find the answer

Given a geometric sequence {an}\{a_n\} satisfies a1+a3=10a_1+a_3=10 and a2+a4=5a_2+a_4=5, then a5=a_5=

Pick one

Solution

Analysis

This problem examines the method to find the fifth term of a geometric sequence by using the general formula of a geometric sequence to find the first term and the common ratio, from which the value of a5a_5 can be determined.

Solution

Given that the geometric sequence {an}\{a_n\} satisfies a1+a3=10a_1+a_3=10 and a2+a4=5a_2+a_4=5,
we have {a1+a1q2=10a1q+a1q3=5\begin{cases}a_1+a_1q^2=10 \\ a_1q+a_1q^3=5\end{cases},
from which we find a1=8a_1=8 and q=12q=\dfrac{1}{2},
thus a5=a1q4=8×116=12a_5=a_1q^4=8×\dfrac{1}{16} =\dfrac{1}{2}.
Therefore, the correct choice is B\boxed{B}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.