18⋅110 As shown, ABCD is an isosceles trapezoid, AD=BC=5,AB=4,DC=10, point C is on DF, and B is the midpoint of the hypotenuse of the right triangle △DEF. Then CF equals (A) 3.25 . (B) 3.5 . (C) 3.75 . (D) 4.0 . (E) 4.25 .
Multiple choice: answer with the letter of the option you want.
Solution
[Solution] Draw BH⊥DF, then BH//EF. Since ABCD is an isosceles trapezoid, ∴CH=21(DC−AB)=3,
then DH=DC−CH=10−3=7. Since B is the midpoint of DE, and DEDB=DFDH, ∴DF=14.
Then CF=DF−CD=4. Therefore, the answer is (D).
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