6. Given that the real part of the expansion of (1+ix)n+2(x∈I) is a polynomial in x, then the sum of the coefficients of this polynomial is (
Pick one
Solution
6. (B).
Let the real part of the expansion be f(x), and the imaginary part be g(x), then f(1) and g(1) are the sums of the coefficients of the real part polynomial and the imaginary part polynomial, respectively. f(1)+ig(1)=(1+i)4n+2=22n+1(cos4π+isin4π)in+2=22n+1[cos(nπ+2π)+isin(nπ+2π)].=22n+1⋅(−1)ni
It is a pure imaginary number, so f(1)=0.
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