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Algebra Difficulty 2.1 Junior Find the answer

Let KK, in square units, be the area of a trapezoid such that the shorter base, the altitude, and the longer base, in that order, are in arithmetic progression. Then:
(A) K  must be an integer\textbf{(A)}\ K \; \text{must be an integer}(B) K  must be a rational fraction(C) K  must be an irrational number\textbf{(B)}\ K \; \text{must be a rational fraction} \\ \textbf{(C)}\ K \; \text{must be an irrational number}(D) K  must be an integer or a rational fraction\textbf{(D)}\ K \; \text{must be an integer or a rational fraction}
(E) taken alone neither  (A)  nor  (B)  nor  (C)  nor  (D)  is true\textbf{(E)}\ \text{taken alone neither} \; \textbf{(A)} \; \text{nor} \; \textbf{(B)} \; \text{nor} \; \textbf{(C)} \; \text{nor} \; \textbf{(D)} \; \text{is true}

Multiple choice: answer with the letter of the option you want.

Solution

From the problem we can set the altitude equal to aa, the shorter base equal to ada-d, and the longer base equal to a+da+d. By the formula for the area of a trapezoid, we have K=a2K=a^2. However, since aa can equal any real number (3,2.7,π)(3, 2.7, \pi), none of the statements A,B,C,DA, B, C, D need to be true, so the answer is E\fbox{E}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.