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Algebra Difficulty 2.7 Junior Find the answer

In a geometric sequence {an}\{a_n\} where each term is positive, if a2a5a8=8a_2a_5a_8=8, then log2a4+log2a6=\log_2a_4+\log_2a_6=

Pick one

Solution

Since in the geometric sequence {an}\{a_n\} with each term being positive, we have a2a5a8=8a_2a_5a_8=8,
then (a5)3=8(a_5)^3=8,
thus a5=2a_5=2,
therefore log2a4+log2a6=log2(a4a6)=log2((a5)2)=2\log_2a_4+\log_2a_6=\log_2(a_4a_6)=\log_2((a_5)^2)=2
Hence, the answer is B\boxed{\text{B}}.

Analysis: By utilizing the condition that in the geometric sequence {an}\{a_n\} with each term being positive, a2a5a8=8a_2a_5a_8=8, we find a5=2a_5=2. Then, by applying the properties of logarithms, we can draw the conclusion.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.