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Algebra Difficulty 3.1 AMC 10/12 Find the answer

In the geometric sequence {an}\{a_n\}, if a3a_3 and a7a_7 are the two roots of the equation 3x211x+9=03x^2-11x+9=0, then the value of a5a_5 is \_\_\_\_\_\_.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Given that a3a_3 and a7a_7 are the two roots of the equation 3x211x+9=03x^2-11x+9=0,
we have a3+a7=113a_3 + a_7 = \frac{11}{3} and a3a7=3a_3 \cdot a_7 = 3.
Therefore, both a3a_3 and a7a_7 are positive.
By the properties of geometric sequences, we have a52=a3a7=3a_5^2 = a_3 \cdot a_7 = 3,
and since the terms of the geometric sequence have the same sign for every other term, we get a5=3a_5 = \sqrt{3}.
Hence, the answer is 3\boxed{\sqrt{3}}.
This problem tests the properties of geometric sequences and the general formula, involving Vieta's formulas, and is considered a basic question.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.