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Geometry Difficulty 5.8 AIME, harder Prove it

[ Intersecting Circles  [Inscribed Quadrilaterals (Miscellaneous)] ]\begin{aligned} & {\left[\begin{array}{l}\text { Intersecting Circles } \\ \text { [Inscribed Quadrilaterals (Miscellaneous)] }\end{array}\right]}\end{aligned}

Two circles intersect at points AA and BB. A line passing through point AA intersects the circles at points MM and NN, different from AA, and a line parallel to it, passing through BB, intersects the circles at points PP and QQ, different from BB. Prove that MN=PQM N = P Q.

Solution

Prove that MPNQM P \| N Q.

## Solution

Since

NQP=NQB=ABQ=BAM=180BPM=180MPQ \angle N Q P=\angle N Q B=\angle A B Q=\angle B A M=180^{\circ}-\angle B P M=180^{\circ}-\angle M P Q

then quadrilateral MNPQM N P Q is a parallelogram. Therefore, MN=PQM N=P Q.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.