Two circles intersect at points A and B. A line passing through point A intersects the circles at points M and N, different from A, and a line parallel to it, passing through B, intersects the circles at points P and Q, different from B. Prove that MN=PQ.
Solution
Prove that MP∥NQ.
## Solution
Since
∠NQP=∠NQB=∠ABQ=∠BAM=180∘−∠BPM=180∘−∠MPQ
then quadrilateral MNPQ is a parallelogram. Therefore, MN=PQ.
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