Maths Olympiad Prep

Library / /163 of 520

Algebra Difficulty 3.0 Junior Find the answer

There are two piles of apples. After moving 2 apples from the first pile to the second pile, the number of apples in the second pile is exactly twice the number of apples in the first pile. If the first pile originally had aa apples, then the second pile originally had ___\_\_\_ apples.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Analysis: Based on the statement "after moving 2 apples from the first pile to the second pile," we can write an algebraic expression for the first pile as a2a-2. Let's assume the second pile originally had bb apples. Then, according to "the number of apples in the second pile is exactly twice the number of apples in the first pile," we can derive an equation 2(a2)=b+22(a-2) = b + 2. Solving for bb will give us the answer.

Let's solve the equation 2(a2)=b+22(a-2) = b + 2:

2(a2)=b+22a4=b+22a6=b \begin{align*} 2(a-2) &= b + 2 \\ 2a - 4 &= b + 2 \\ 2a - 6 &= b \end{align*}

Therefore, the second pile originally had 2a6\boxed{2a - 6} apples.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.