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Algebra Difficulty 4.5 AIME Find the answer

5. Given (2000a)(2000-a).
(1998a)=1999(1998-a)=1999. Then, (2000a)2+(1998(2000-a)^{2}+(1998- a)2=a)^{2}= \qquad

A number or a short expression. Spacing and $ signs are ignored.

Solution

5.40025.4002

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.