If a=0, the equation obviously holds. Therefore, we can assume a,b,c are positive integers,
a=p1q1⋯psσ3,b=p1β1⋯p3β3,c=p1γ1⋯p3γ3.
By Corollary 4, we get
(a,[b,c])=p1η1⋯ppjηj,ηj=min(αj,max(βj,γj)),1⩽j⩽s[(a,b),(a,c)]=p1τ1⋯psτs,τj=max(min(αj,βj),min(αj,γj)),1⩽j⩽s
It is easy to verify that, regardless of the size relationship between αj,βj,γj, we always have τj=ηj(1⩽j⩽s). This proves the desired conclusion. It is relatively difficult to prove this relationship directly using the method of §4.