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Algebra Difficulty 4.7 AIME Find the answer

6. The graph of the linear function y=k(x1)y=k(x-1) passes through the point M(1,2)M(-1,-2). Then its intersection with the yy-axis is:

Pick one

Solution

6. A.

From the problem, we know that k(11)=2k(-1-1)=-2, which means k=1k=1. Therefore, the function expression is y=x1y=x-1. Substituting x=0x=0 into it, we get y=1y=-1. Hence, the intersection point of its graph with the yy-axis is (0,1)(0,-1).

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.