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Geometry Difficulty 2.2 Junior Find the answer

A triangle is circumscribed about a circle of radius rr inches. If the perimeter of the triangle is PP inches and the area is KK square inches, then PK\frac{P}{K} is:

Pick one

Solution

The area KK of the triangle can be expressed in terms of its inradius rr and its semiperimeter ss as:
K=r×s=r×P2K = r \times s = r \times \frac{P}{2}
So, PK=(C) 2r\frac{P}{K} = \boxed{\textbf{(C) } \frac{2}{r}}.
~ proloto

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.