8. In Rt △ABC, the altitude CD on the hypotenuse AB is 3, extend DC to point P, such that CP=2, connect AP, draw BF⊥AP, intersecting CD and AP at points E and F respectively. Then the length of segment DE is
A number or a short expression. Spacing and $ signs are ignored.
Solution
8. 59. As shown in Figure 5, let AD=a. In the right triangle △ABC, given CD=3,CD⊥AB, we know BD=a9. Notice that, in the right triangles △APD∼△EBD,
then BDDE=PDAD⇒DE=a9×5a=59.
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