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Algebra Difficulty 2.5 Junior Find the answer

Shuxin begins with 10 red candies, 7 yellow candies, and 3 blue candies. After eating some of the candies, there are equal numbers of red, yellow, and blue candies remaining. What is the smallest possible number of candies that Shuxin ate?

A number or a short expression. Spacing and $ signs are ignored.

Solution

For there to be equal numbers of each colour of candy, there must be at most 3 red candies and at most 3 yellow candies, since there are 3 blue candies to start. Thus, Shuxin ate at least 7 red candies and at least 4 yellow candies. This means that Shuxin ate at least 7+4=117+4=11 candies. We note that if Shuxin eats 7 red candies, 4 yellow candies, and 0 blue candies, there will indeed be equal numbers of each colour.

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