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Geometry Difficulty 4.4 AIME Find the answer

Points A,B,C,DA, B, C, D lie on a circle in that order such that ABBC=DACD\frac{A B}{B C}=\frac{D A}{C D}. If AC=3A C=3 and BD=BC=4B D=B C=4, find ADA D.

A number or a short expression. Spacing and $ signs are ignored.

Solution

By Ptolemy's theorem, we have ABCD+BCDA=ACBD=34=12A B \cdot C D+B C \cdot D A=A C \cdot B D=3 \cdot 4=12. Since the condition implies ABCD=BCDAA B \cdot C D=B C \cdot D A, we have DA=6BC=32D A=\frac{6}{B C}=\frac{3}{2}.

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