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HMMT November

Geometry Difficulty 4.4 AIME Find the answer

Points A,B,C,DA, B, C, D lie on a circle in that order such that ABBC=DACD\frac{A B}{B C}=\frac{D A}{C D}. If AC=3A C=3 and BD=BC=4B D=B C=4, find ADA D.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

By Ptolemy's theorem, we have AB⋅CD+BC⋅DA=AC⋅BD=3⋅4=12A B \cdot C D+B C \cdot D A=A C \cdot B D=3 \cdot 4=12. Since the condition implies AB⋅CD=BC⋅DAA B \cdot C D=B C \cdot D A, we have DA=6BC=32D A=\frac{6}{B C}=\frac{3}{2}.

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