Points A,B,C,D lie on a circle in that order such that BCAB=CDDA. If AC=3 and BD=BC=4, find AD.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
By Ptolemy's theorem, we have AB⋅CD+BC⋅DA=AC⋅BD=3⋅4=12. Since the condition implies AB⋅CD=BC⋅DA, we have DA=BC6=23.
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