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Geometry Difficulty 4.7 AIME Find the answer

Let aa and bb be positive real numbers. Determine the minimum possible value of a2+b2+(a1)2+b2+a2+(b1)2+(a1)2+(b1)2\sqrt{a^{2}+b^{2}}+\sqrt{(a-1)^{2}+b^{2}}+\sqrt{a^{2}+(b-1)^{2}}+\sqrt{(a-1)^{2}+(b-1)^{2}}

A number or a short expression. Spacing and $ signs are ignored.

Solution

Let ABCDA B C D be a square with A=(0,0),B=(1,0),C=(1,1),D=(0,1)A=(0,0), B=(1,0), C=(1,1), D=(0,1), and PP be a point in the same plane as ABCDA B C D. Then the desired expression is equivalent to AP+BP+CP+DPA P+B P+C P+D P. By the triangle inequality, AP+CPACA P+C P \geq A C and BP+DPBDB P+D P \geq B D, so the minimum possible value is AC+BD=22A C+B D=2 \sqrt{2}. This is achievable when a=b=12a=b=\frac{1}{2}, so we are done.

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