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Algebra Difficulty 4.9 AIME Find the answer

aa and bb are integers such that a+b=15+216a+\sqrt{b}=\sqrt{15+\sqrt{216}}. Compute a/ba / b.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Squaring both sides gives a2+b+2ab=15+216a^{2}+b+2 a \sqrt{b}=15+\sqrt{216}; separating rational from irrational parts, we get a2+b=15,4a2b=216a^{2}+b=15,4 a^{2} b=216, so a2a^{2} and bb equal 6 and 9.a9 . a is an integer, so a2=9,b=6a/b=3/6=1/2a^{2}=9, b=6 \Rightarrow a / b=3 / 6=1 / 2. (We cannot have a=3a=-3, since a+ba+\sqrt{b} is positive.)

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