Given positive integers find the least positive integer such that among any distinct integers in the interval there are three pair-wise distinct numbers that their sum is zero.
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Solution
To solve the problem, we need to find the least positive integer such that among any distinct integers in the interval , there are three pair-wise distinct numbers whose sum is zero.
### Analysis
1. General Strategy:
- We need to ensure that for any selection of distinct numbers from the interval , there exists a triple such that .
2. **Case 1: for **:
- If and are both even and equal, becomes .
- The interval has numbers.
- To avoid having a trio summing to zero, every choice of three distinct integers must include a number and its negative, which would already make their sum zero unless balanced by zero itself.
- The smallest size that assures a zero sum without including zero or its complementary negative pair would require . However, to necessarily include a zero sum, start with the smallest that forces inclusion, which is .
3. **Case 2: General case (including non-equal and )**:
- For arbitrary and which do not satisfy , the interval length is .
- To guarantee a sum of zero, consider the maximum coverage which should at least span from or more to definitely include numbers and their negatives with sufficient span to include zero.
- Thus, setting forces the selection of at least enough elements to capture not only distinct values but integrals that span a potential triple summing zero.
### Conclusion
The least positive integer that satisfies the conditions varies based on specific values of and . Hence, we determine:
Thus, the minimum value of is:
This covers both specific and general scenarios for selecting numbers from the interval such that three distinct numbers will sum to zero.