Maths Olympiad Prep

Library / HMMT November /63 of 672

HMMT November

Geometry Difficulty 4.6 AIME Find the answer

Isosceles trapezoid ABCDABCD with bases ABAB and CDCD has a point PP on ABAB with AP=11,BP=27AP=11, BP=27, CD=34CD=34, and ∠CPD=90∘\angle CPD=90^{\circ}. Compute the height of isosceles trapezoid ABCDABCD.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Drop projections of A,P,BA, P, B onto CDCD to get A′,P′,B′A', P', B'. Since A′B′=38A'B'=38 and CD=34CD=34, we get that DA′=CB′=2DA'=CB'=2. Thus, P′D=9P'D=9 and P′C=25P'C=25. Hence, the answer is PP′=P′D⋅P′C=15PP'=\sqrt{P'D \cdot P'C}=15.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.