Determine all positive integers that satisfy the following condition: for all and relatively prime to we have
Solution
To determine all positive integers that satisfy the given condition, we need to analyze when if and only if for all and that are relatively prime to .
### Step 1: Analyze the given condition
The problem requires:
- if and only if .
### Step 2: Translating the conditions
1. If Part: If , then for some integer . So, implies .
2. Only If Part: If , then there exists some integer such that . This situation implies .
Consider using group theory concepts, including units modulo . The set of integers coprime with , under multiplication modulo , forms the **multiplicative group of units mod **, denoted by .
### Step 3: Conditions on the structure of
For both conditions to hold:
- forms a group where every element has its inverse to satisfy the divisors such that .
- Specifically, for all in , indicating that each element in is its own inverse.
### Step 4: Determine such that every unit in is its own inverse
To solve the problem, every element in must be its own inverse. This is equivalent to demanding that the group order must be a power of 2, as groups with elements all self-invertible are those isomorphic to elementary abelian 2-groups.
### Step 5: Identifying all eligible
From the conditions operating on , the integer can be characterized as the product of distinct prime powers where the for some , and where each , remains power of two.
For , this includes , resulting into:
- .
Thus, the list of positive integers satisfying the conditions of the problem statement are:
This completes the problem's solving process.