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Geometry Difficulty 5.0 AIME Find the answer

Given points aa and bb in the plane, let aba \oplus b be the unique point cc such that abca b c is an equilateral triangle with a,b,ca, b, c in the clockwise orientation. Solve (x(0,0))(1,1)=(1,1)(x \oplus(0,0)) \oplus(1,1)=(1,-1) for xx.

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Solution

It is clear from the definition of \oplus that b(ab)=ab \oplus(a \oplus b)=a and if ab=ca \oplus b=c then bc=ab \oplus c=a and ca=bc \oplus a=b. Therefore x(0,0)=(1,1)(1,1)=(13,0)x \oplus(0,0)=(1,1) \oplus(1,-1)=(1-\sqrt{3}, 0). Now this means x=(0,0)(13,0)=(132,332)x=(0,0) \oplus(1-\sqrt{3}, 0)=\left(\frac{1-\sqrt{3}}{2}, \frac{3-\sqrt{3}}{2}\right).

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