Suppose $n^{2}-3000=x^{2}$, so $n^{2}-x^{2}=3000$. This factors as $(n-x)(n+x)=3000$. Thus, we have $n-x=2a$ and $n+x=2b$ for some positive integers $a, b$ such that $ab=750$ and $a<b$. Therefore, we have $n=a+b$, so the sum will be just the sum of divisors of $750=2 \cdot 3 \cdot 5^{3}$, which is $$(1+2)(1+3)(1+5+25+125)=1872$$.