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Combinatorics Difficulty 4.9 AIME Find the answer

Compute n60=02n59=0n60n2=0n3n1=0n2n0=0n11\sum_{n_{60}=0}^{2} \sum_{n_{59}=0}^{n_{60}} \cdots \sum_{n_{2}=0}^{n_{3}} \sum_{n_{1}=0}^{n_{2}} \sum_{n_{0}=0}^{n_{1}} 1

A number or a short expression. Spacing and $ signs are ignored.

Solution

The given sum counts the number of non-decreasing 61-tuples of integers (n0,,n60)\left(n_{0}, \ldots, n_{60}\right) from the set {0,1,2}\{0,1,2\}. Such 61-tuples are in one-to-one correspondence with strictly increasing 61-tuples of integers (m0,,m60)\left(m_{0}, \ldots, m_{60}\right) from the set {0,1,2,,62}\{0,1,2, \ldots, 62\}: simply let mk=nk+km_{k}=n_{k}+k. But the number of such (m0,,m60)\left(m_{0}, \ldots, m_{60}\right) is almost by definition (6361)=(632)=1953\binom{63}{61}=\binom{63}{2}=1953.

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Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.