For fixed denominators $a<b$ (with sum 10), we maximize the sum of the fractions by giving the smaller denominator as large a numerator as possible: $8 / a+1 / b$. Then, if $a \geq 2$, this quantity is at most $8 / 2+1 / 1=5$, which is clearly smaller than the sum we get by setting $a=1$, namely $8 / 1+1 / 9=73 / 9$. So this is the answer.