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Algebra Difficulty 2.3 Junior Find the answer

A factory makes chocolate bars. Five boxes, labelled V,W,X,Y,ZV, W, X, Y, Z, are each packed with 20 bars. Each of the bars in three of the boxes has a mass of 100 g. Each of the bars in the other two boxes has a mass of 90 g. One bar is taken from box VV, two bars are taken from box WW, four bars are taken from box XX, eight bars are taken from box YY, and sixteen bars are taken from box ZZ. The total mass of these bars taken from the boxes is 2920 g. Which boxes contain the 90 g bars?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

The number of bars taken from the boxes is 1+2+4+8+16=311+2+4+8+16=31. If these bars all had mass 100 g, their total mass would be 3100 g. Since their total mass is 2920 g, they are 3100 g2920 g=180 g3100 \mathrm{~g}-2920 \mathrm{~g}=180 \mathrm{~g} lighter. Since all of the bars have a mass of 100 g or of 90 g, then it must be the case that 18 of the bars are each 10 g lighter (that is, have a mass of 90 g). Thus, we want to write 18 as the sum of two of 1,2,4,8,161,2,4,8,16 in order to determine the boxes from which the 90 g bars were taken. We note that 18=2+1618=2+16 and so the 90 g bars must have been taken from box WW and box ZZ.

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