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Algebra Difficulty 5.1 AIME, harder Find the answer

Let f(x)=x2+ax+bf(x)=x^{2}+a x+b and g(x)=x2+cx+dg(x)=x^{2}+c x+d be two distinct real polynomials such that the xx-coordinate of the vertex of ff is a root of gg, the xx-coordinate of the vertex of gg is a root of ff and both ff and gg have the same minimum value. If the graphs of the two polynomials intersect at the point (2012, - 2012), what is the value of a+ca+c ?

A number or a short expression. Spacing and $ signs are ignored.

Solution

It is clear, by symmetry, that 2012 is the equidistant from the vertices of the two quadratics. Then it is clear that reflecting ff about the line x=2012x=2012 yields gg and vice versa. Thus the average of each pair of roots is 2012 . Thus the sum of the four roots of ff and gg is 8048 , so a+c=8048a+c=-8048.

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