Maths Olympiad Prep

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Algebra Difficulty 5.1 AIME, harder Find the answer

Given that rr and ss are relatively prime positive integers such that rs=2(2+10)5(3+5)\frac{r}{s} = \frac{2(\sqrt{2} + \sqrt{10})}{5(\sqrt{3 + \sqrt{5}})}, find rr and ss.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Squaring both sides of the given equation yields r2s2=4(12+45)25(3+5)=16(3+5)25(3+5)=1625\frac{r^{2}}{s^{2}} = \frac{4(12 + 4 \sqrt{5})}{25(3 + \sqrt{5})} = \frac{16(3 + \sqrt{5})}{25(3 + \sqrt{5})} = \frac{16}{25}. Because rr and ss are positive and relatively prime, then by inspection, r=4r = 4 and s=5s = 5.

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