Given that r and s are relatively prime positive integers such that sr=5(3+5)2(2+10), find r and s.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Squaring both sides of the given equation yields s2r2=25(3+5)4(12+45)=25(3+5)16(3+5)=2516. Because r and s are positive and relatively prime, then by inspection, r=4 and s=5.
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