Let R be the region in the Cartesian plane of points (x,y) satisfying x≥0,y≥0, and x+y+⌊x⌋+⌊y⌋≤5. Determine the area of R.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
We claim that a point in the first quadrant satisfies the desired property if the point is below the line x+y=3 and does not satisfy the desired property if it is above the line. To see this, for a point inside the region, x+y<3 and ⌊x⌋+⌊y⌋≤x+y<3 However, ⌊x⌋+⌊y⌋ must equal to an integer. Thus, ⌊x⌋+⌊y⌋≤2. Adding these two equations, x+y+⌊x⌋+⌊y⌋<5, which satisfies the desired property. Conversely, for a point outside the region, ⌊x⌋+⌊y⌋+{x}+{y}=x+y>3 However, {x}+{y}<2. Thus, ⌊x⌋+⌊y⌋>1, so ⌊x⌋+⌊y⌋≥2, implying that x+y+⌊x⌋+⌊y⌋>5. To finish, R is the region bounded by the x -axis, the y -axis, and the line x+y=3 is a right triangle whose legs have length 3. Consequently, R has area 29.
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