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CEMC Pascal

Algebra Difficulty 1.5 Junior Find the answer

If m+1=n−23m+1=\frac{n-2}{3}, what is the value of 3m−n3 m-n?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since m+1=n−23m+1=\frac{n-2}{3}, then 3(m+1)=n−23(m+1)=n-2. This means that 3m+3=n−23 m+3=n-2 and so 3m−n=−2−3=−53 m-n=-2-3=-5.

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