Maths Olympiad Prep

Library / /67 of 348

Geometry Difficulty 4.7 AIME Find the answer

In circle ω\omega, two perpendicular chords intersect at a point PP. The two chords have midpoints M1M_{1} and M2M_{2} respectively, such that PM1=15P M_{1}=15 and PM2=20P M_{2}=20. Line M1M2M_{1} M_{2} intersects ω\omega at points AA and BB, with M1M_{1} between AA and M2M_{2}. Compute the largest possible value of BM2AM1B M_{2}-A M_{1}.

A number or a short expression. Spacing and $ signs are ignored.

Solution

Let OO be the center of ω\omega and let MM be the midpoint of ABA B (so MM is the foot of OO to M1M2M_{1} M_{2} ). Since OM1PM2O M_{1} P M_{2} is a rectangle, we easily get that MM1=16M M_{1}=16 and MM2=9M M_{2}=9. Thus, BM2AM1=B M_{2}-A M_{1}= MM1MM2=7M M_{1}-M M_{2}=7

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.