Let ABCD be a rectangle with AB=3 and BC=7. Let W be a point on segment AB such that AW=1. Let X,Y,Z be points on segments BC,CD,DA, respectively, so that quadrilateral WXYZ is a rectangle, and BX<XC. Determine the length of segment BX.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
We note that ∠YXC=90−∠WXB=∠XWB=90−∠AWZ=∠AZW gives us that XYC≅ZWA and XYZ∼WXB. Consequently, we get that YC=AW=1. From XYZ∼WXB, we get that BWBX=CXCY⇒2BX=7−BX1 from which we get BX2−7BX+2=0⇒BX=27−41 (since we have BX<CX ).
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