Let x be a real number. Find the maximum value of 2x(1−x).
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Consider the function 2y. This is monotonically increasing, so to maximize 2y, you simply want to maximize y. Here, y=x(1−x)=−x2+x is a parabola opening downwards. The vertex of the parabola occurs at x=(−1)/(−2)=1/2, so the maximum value of the function is 2(1/2)(1/2)=42.
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