Maths Olympiad Prep

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Algebra Difficulty 2.8 Junior Find the answer

In the 5×55 \times 5 grid shown, 15 cells contain X's and 10 cells are empty. What is the smallest number of X's that must be moved so that each row and each column contains exactly three X's?

A number or a short expression. Spacing and $ signs are ignored.

Solution

Each of the first and second columns has 4 X's in it, which means that at least 2 X's need to be moved. We will now show that this can be actually done by moving 2 X's. Each of the first and second rows has 4 X's in it, so we move the two X's on the main diagonals, since this will remove X's from the first and second columns and the first and second rows simultaneously. The fifth column starts with one X in it, so we move the two X's to the fifth column into the rows that only contain 2 X's. Doing this, we obtain a grid where each row and column contains exactly three X's.

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