Maths Olympiad Prep

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Combinatorics Difficulty 5.3 AIME, harder Find the answer

Let RR be the rectangle in the Cartesian plane with vertices at (0,0),(2,0),(2,1)(0,0),(2,0),(2,1), and (0,1)(0,1). RR can be divided into two unit squares, as shown; the resulting figure has seven edges. How many subsets of these seven edges form a connected figure?

A number or a short expression. Spacing and $ signs are ignored.

Solution

We break this into cases. First, if the middle edge is not included, then there are 65=306 * 5=30 ways to choose two distinct points for the figure to begin and end at. We could also allow the figure to include all or none of the six remaining edges, for a total of 32 connected figures not including the middle edge. Now let's assume we are including the middle edge. Of the three edges to the left of the middle edge, there are 7 possible subsets we can include (8 total subsets, but we subtract off the subset consisting of only the edge parallel to the middle edge since it's not connected). Similarly, of the three edges to the right of the middle edge, there are 7 possible subsets we can include. In total, there are 49 possible connected figures that include the middle edge. Therefore, there are 32+49=8132+49=81 possible connected figures.

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Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.