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Algebra Difficulty 2.8 Junior Find the answer

In the sum shown, P,QP, Q and RR represent three different single digits. What is the value of P+Q+RP+Q+R?

P 7 R + 39 R R Q 0\text{P 7 R + 39 R R Q 0}

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since the second number being added is greater than 300 and the sum has hundreds digit RR, then RR cannot be 0. From the ones column, we see that the ones digit of R+RR+R is 0. Since R0R \neq 0, then R=5R=5. This makes the sum

P75+3955Q0\begin{array}{r} P 75 \\ +\quad 395 \\ \hline 5 Q 0 \end{array}

Since 1+7+9=171+7+9=17, we get Q=7Q=7 and then 1+P+3=51+P+3=5 and so P=1P=1, giving the final sum

11175+395570\begin{array}{r} 11 \\ 175 \\ +\quad 395 \\ \hline 570 \end{array}

Therefore, P+Q+R=1+7+5=13P+Q+R=1+7+5=13.

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Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.