We work backwards through the given information. At the end, there is 1 candy remaining. Since $\frac{5}{6}$ of the candies are removed on the fifth day, this 1 candy represents $\frac{1}{6}$ of the candies left at the end of the fourth day. Thus, there were $6 imes 1=6$ candies left at the end of the fourth day. Since $\frac{4}{5}$ of the candies are removed on the fourth day, these 6 candies represent $\frac{1}{5}$ of the candies left at the end of the third day. Thus, there were $5 imes 6=30$ candies left at the end of the third day. Since $\frac{3}{4}$ of the candies are removed on the third day, these 30 candies represent $\frac{1}{4}$ of the candies left at the end of the second day. Thus, there were $4 imes 30=120$ candies left at the end of the second day. Since $\frac{2}{3}$ of the candies are removed on the second day, these 120 candies represent $\frac{1}{3}$ of the candies left at the end of the first day. Thus, there were $3 imes 120=360$ candies left at the end of the first day. Since $\frac{1}{2}$ of the candies are removed on the first day, these 360 candies represent $\frac{1}{2}$ of the candies initially in the bag. Thus, there were $2 imes 360=720$ in the bag at the beginning.