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Algebra Difficulty 2.8 Junior Find the answer

If 211×65=4x×3y2^{11} \times 6^{5}=4^{x} \times 3^{y} for some positive integers xx and yy, what is the value of x+yx+y?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Manipulating the left side, 211×65=211×(2×3)5=211×25×35=216×352^{11} \times 6^{5}=2^{11} \times(2 \times 3)^{5}=2^{11} \times 2^{5} \times 3^{5}=2^{16} \times 3^{5}. Since 4x×3y=216×354^{x} \times 3^{y}=2^{16} \times 3^{5} and xx and yy are positive integers, then y=5y=5 (because 4x4^{x} has no factors of 3). This also means that 4x=2164^{x}=2^{16}. Since 4x=(22)x=22x4^{x}=\left(2^{2}\right)^{x}=2^{2x}, then 4x=2164^{x}=2^{16} gives 22x=2162^{2x}=2^{16} and so 2x=162x=16 or x=8x=8. Therefore, x+y=8+5=13x+y=8+5=13.

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