Maths Olympiad Prep

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Geometry Difficulty 5.1 AIME, harder Find the answer

Let ABCDA B C D be a convex quadrilateral inscribed in a circle with shortest side ABA B. The ratio [BCD]/[ABD][B C D] /[A B D] is an integer (where [XYZ][X Y Z] denotes the area of triangle XYZX Y Z.) If the lengths of AB,BC,CDA B, B C, C D, and DAD A are distinct integers no greater than 10, find the largest possible value of ABA B.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Note that [BCD][ABD]=12BCCDsinC12DAABsinA=BCCDDAAB\frac{[B C D]}{[A B D]}=\frac{\frac{1}{2} B C \cdot C D \cdot \sin C}{\frac{1}{2} D A \cdot A B \cdot \sin A}=\frac{B C \cdot C D}{D A \cdot A B} since A\angle A and C\angle C are supplementary. If AB6A B \geq 6, it is easy to check that no assignment of lengths to the four sides yields an integer ratio, but if AB=5A B=5, we can let BC=10B C=10, CD=9C D=9, and DA=6D A=6 for a ratio of 3 . The maximum value for ABA B is therefore 5.

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