Maths Olympiad Prep

Library / HMMT November /344 of 672

HMMT November

Combinatorics Difficulty 5.0 AIME, harder Find the answer

On an 8×88 \times 8 chessboard, 6 black rooks and kk white rooks are placed on different cells so that each rook only attacks rooks of the opposite color. Compute the maximum possible value of kk.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

The answer is k=14k=14. For a valid construction, place the black rooks on cells (a,a)(a, a) for 2≤a≤72 \leq a \leq 7 and the white rooks on cells (a,a+1)(a, a+1) and (a+1,a)(a+1, a) for 1≤a≤71 \leq a \leq 7. Now, we prove the optimality. As rooks can only attack opposite color rooks, the color of rooks in each row is alternating. The difference between the number of black and white rooks is thus at most the number of rooks. Thus, k≤6+8=14k \leq 6+8=14.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.