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Algebra Difficulty 4.7 AIME Find the answer

Given ef=34\frac{e}{f}=\frac{3}{4} and e2+f2=15\sqrt{e^{2}+f^{2}}=15, find efef.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

We know that ef=34\frac{e}{f}=\frac{3}{4} and e2+f2=15\sqrt{e^{2}+f^{2}}=15. Solving for ee and ff, we find that e2+f2=225e^{2}+f^{2}=225, so 16e2+16f2=360016 e^{2}+16 f^{2}=3600, so (4e)2+(4f)2=3600(4 e)^{2}+(4 f)^{2}=3600, so (3f)2+(4f)2=3600(3 f)^{2}+(4 f)^{2}=3600, so f2(32+42)=3600f^{2}\left(3^{2}+4^{2}\right)=3600, so 25f2=360025 f^{2}=3600, so f2=144f^{2}=144 and f=12f=12. Thus, e=3412=9e=\frac{3}{4} \cdot 12=9. Therefore, ef=912=108\boldsymbol{e f}=9 * 12=\mathbf{1 0 8}.

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