The list p,q,r,s consists of four consecutive integers listed in increasing order. If p+s=109, what is the value of q+r?
A number or a short expression. Spacing and $ signs are ignored.
Solution
Since p,q,r,s is a list of consecutive integers in increasing order, then q is 1 more than p and r is 1 less than s. This means that q+r=(p+1)+(s−1)=p+s=109. Therefore, q+r=109.
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