Maths Olympiad Prep

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Algebra Difficulty 5.0 AIME, harder Find the answer

The equation x2+2x=ix^{2}+2 x=i has two complex solutions. Determine the product of their real parts.

A number or a short expression. Spacing and $ signs are ignored.

Solution

The solutions are x+1=±eiπ824x+1= \pm e^{\frac{i \pi}{8}} \sqrt[4]{2}. The desired product is then (1+cos(π8)24)(1cos(π8)24)=1cos2(π8)2=1(1+cos(π4))22=122\left(-1+\cos \left(\frac{\pi}{8}\right) \sqrt[4]{2}\right)\left(-1-\cos \left(\frac{\pi}{8}\right) \sqrt[4]{2}\right)=1-\cos ^{2}\left(\frac{\pi}{8}\right) \sqrt{2}=1-\frac{\left(1+\cos \left(\frac{\pi}{4}\right)\right)}{2} \sqrt{2}=\frac{1-\sqrt{2}}{2}

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Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.