Let be a triangle with obtuse. The [i]-excircle[/i] is a circle in the exterior of that is tangent to side of the triangle and tangent to the extensions of the other two sides. Let , be the feet of the altitudes from and to lines and , respectively. Can line be tangent to the -excircle?
Solution
To determine whether the line can be tangent to the -excircle of , where is obtuse, we start by analyzing the geometric properties involved.
### Step 1: Understanding the Geometry
1. Excircle Properties: The -excircle is a circle in the exterior of that is tangent to and the extensions of and . It is centered at the excenter opposite to vertex .
2. Altitude Feet: Points and are the feet of the perpendiculars from and to the lines and , respectively.
### Step 2: Analyzing Line
- The line is the line segment connecting and , which lie on the sides and or their extensions due to the obtuseness of .
### Step 3: Tangency Condition
- For line to be tangent to the -excircle, it would require that the perpendicular distance from the excenter to line be equal to the radius of the -excircle.
### Step 4: Geometric Constraints
- Since is obtuse, the altitude will lie inside the triangle, and will lie outside the triangle.
- This configuration suggests that line intersects or passes quite far from the -excircle in relation to the sides and .
- The specific positions of in relation to the -excircle imply that , instead of being tangent, intersects with circles tangent or externally relative to the triangle sides.
### Conclusion
Given the constructions and the restrictions associated with an obtuse angle and the nature of excircles, cannot simultaneously touch the -excircle. Therefore, line cannot be tangent to the -excircle.
The reason derives from the incompatibility of the areas of tangency of the -excircle with the line segment as positioned relative to an obtuse .