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Geometry Difficulty 4.5 AIME Find the answer

Let ABCDABCD be a trapezoid such that ABCD,BAC=25,ABC=125AB \parallel CD, \angle BAC=25^{\circ}, \angle ABC=125^{\circ}, and AB+AD=CDAB+AD=CD. Compute ADC\angle ADC.

A number or a short expression. Spacing and $ signs are ignored.

Solution

Construct the parallelogram ABEDABED. From the condition AB+AD=CDAB+AD=CD, we get that EC=AD=EBEC=AD=EB. Thus, ADC=BEC=1802BCE=180255=70\angle ADC=\angle BEC=180^{\circ}-2 \angle BCE=180^{\circ}-2 \cdot 55^{\circ}=70^{\circ}.

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